Answer:
The correct option is;
5 electrons
Explanation:
The charge of the proton is equal to 1.602 × 10⁻¹⁹C while the charge of one electron is -1.602 × 10⁻¹⁹C
Therefore, given that the atom is to be electrically neutral, we have;
The initial charge of the atom = 5 × 1.602 × 10⁻¹⁹C = 8.01 × 10⁻¹⁹C
The charge of the added electron + The charge of the present proton = 0
Therefore;
The charge of the added electron + 8.01 × 10⁻¹⁹C = 0
The charge of the added electrons = 0 - 8.01 × 10⁻¹⁹C = -8.01 × 10⁻¹⁹C
The charge of one electron = -1.602 × 10⁻¹⁹C
The number of electrons = The charge of the added electrons/(The charge of one electron)
The number of electrons = -8.01 × 10⁻¹⁹C/(-1.602 × 10⁻¹⁹C) = 5 electrons
The number of electrons to be added = 5 electrons.