Question

2. A jackscrew with a handle 30.0 cm long is used to lift a car sitting on the jack.

The car raised 2.0 cm with every full turn of the handle. What is the ideal
mechanical advantage of the jack? (C = 23c).

Answer 1

`94.25`

Step-by-step explanation:

Given: Handle of jackscrew is 30 cm long. Also, the car raised 2.0 cm with every full turn of the handle.

To find: ideal mechanical advantage of the jack

Solution:

Let
`d_e` denotes the distance over which the effort is applied and
`d_r` denotes the distance that the load travels.

Here,

`d_r=2\,\,cm`

`d_e=2\pi(length\,\,of\,\,the\,\,handle)=2\pi(30)=60\pi`

So,

Ideal mechanical advantage of the jack
`(d_e)/(d_r)=(60\pi)/(2)=30\pi=30((22)/(7))=94.25`