Question

(look at the image) can i get help on this?

Answer 1

Explanation:

1.

(2x-11)° = 105° (vertical angles)

2x - 11 = 105

2x = 105 + 11

2x = 116

x = 116/2

x = 58

`m\angle BEC = (2x - 11)\degree \\</p><p>m\angle BEC = (2* 58-11)\degree \\</p><p>m\angle BEC = (116-11)\degree \\</p><p>\huge m\angle BEC = 105\degree \\</p><p>m\angle AEB =180\degree - 105\degree \\</p><p>(straight \: line \: \angle 's) \\</p><p>\huge m\angle AEB =75\degree \\</p><p>m\angle CED=m\angle AEB = 75\degree\\ (vertical \:\angle' s) \\`

2.

`(6x + 19)\degree + x \degree = 180\degree \\(straight \: line \: \angle 's) \\</p><p>(7x + 19) \degree = 180\degree\\</p><p>7x + 19 = 180\\</p><p>7x = 180 - 19\\</p><p>7x = 161\degree \\</p><p>x =(161)/(7)\\</p><p>x = 23\\</p><p>m\angle AEB=(6x + 19)\degree \\</p><p>m\angle AEB=(6* 23+ 19)\degree \\</p><p>m\angle AEB=(138+ 19)\degree \\</p><p>\huge m\angle AEB=157\degree \\</p><p>m\angle CED=m\angle AEB = 157\degree\\ (vertical \:\angle' s) \\</p><p>m\angle BEC = x\degree \\</p><p>\huge m\angle BEC = 23\degree \\</p><p>m\angle AED =m\angle BEC=23\degree \\</p><p>(vertical \:\angle' s) \\</p><p>`