Answer:
![\boxed {\tt f(3)= 10}](https://img.qammunity.org/2021/formulas/mathematics/college/hxyexmf6a4kno3kswsf8itmvxtyuj8wbgt.png)
Explanation:
We are given the function:
![f(x)= -x^2+19](https://img.qammunity.org/2021/formulas/mathematics/college/mx7uy3lszj4bt3gsvjzcoh4o2n7nznes1u.png)
We want to find f(3), therefore we must substitute 3 in for x.
![f(3)= -(3)^2+19](https://img.qammunity.org/2021/formulas/mathematics/college/31lsjyeifeivd79x60sbmsyjflq0yfkm0e.png)
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. Evaluate the exponent.
![f(3)= -(9)+19](https://img.qammunity.org/2021/formulas/mathematics/college/f0q2xlxzpln7qvbf9885fc1235y7r971ej.png)
![f(3)=-9+19](https://img.qammunity.org/2021/formulas/mathematics/college/h1bsawoai5o0rg4za6po5a0vem8zbmawtd.png)
Add 19 to -9.
![f(3)= 10](https://img.qammunity.org/2021/formulas/mathematics/college/txpd6n00fbntcrzvl3duwrjcjk7spoh5cr.png)
For the function f(x)=-x²+19, f(3)= 10