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Help can you walk me through this?-example-1

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Steps: ∠EFG = 122°

1. You know ∠1 = ∠2 and ∠1 = (3x - 2), therefore ∠2 also equals (3x - 2).


2. ∠EFG = (5x + 17), and ∠1 + ∠2 = ∠EFG based on the graph.


3. Using what you know, make an equation to find value of x:

∠EFG = ∠1 + ∠2

(5x + 17) = (3x - 2) + (3x - 2)

5x + 17 = 3x + 3x - 2 - 2

5x + 17 = 6x - 4 (Subtract 5x from both sides)

17 = x - 4 (Add 4 to both sides)

21 = x

x = 21


4. Plug value of x into (5x + 17) to find ∠EFG

5(21) + 17

105 + 17

122°
User Philolegein
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