Answer:
a. 409.5 m/s b. f₁ = 136.5 Hz, f₂ = 409.5 Hz, f₃ = 682.5 Hz
Step-by-step explanation:
a. The speed of sound v in a gas is v = √(B/ρ) where B = bulk modulus and ρ = density. Given that on Venus, B = 1.09 × 10⁷ N/m² and ρ = 65.0 kg/m³
So, v = √(B/ρ)
= √(1.09 × 10⁷ N/m²/65.0 kg/m³)
= √(0.01677 × 10⁷ Nm/kg)
= √(0.1677 × 10⁶ Nm/kg)
= 0.4095 × 10³ m/s
= 409.5 m/s
b. For a pipe open at one end, the frequency f = nv/4L where n = mode of wave = 1,3,5,.., v = speed of wave = 409.5 m/s and L = length of pipe = 75.0 cm = 0.75 m
Now, for the first mode or frequency, n = 1
f₁ = v/4L
= 409.5 m/s ÷ (4 × 0.75 m)
= 409,5 m/s ÷ 3 m
= 136.5 Hz
Now, for the second mode or frequency, n = 2
f₂ = 3v/4L
= 3 ×409.5 m/s ÷ (4 × 0.75 m)
= 3 × 409,5 m/s ÷ 3 m
= 3 × 136.5 Hz
= 409.5 Hz
Now, for the third mode or frequency, n = 5
f₃ = 5v/4L
= 5 × 409.5 m/s ÷ (4 × 0.75 m)
= 5 × 409,5 m/s ÷ 3 m
= 682.5 Hz