Question

P9. Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1 Mbps link. Users are generating data at a rate of 100 kbps when busy, but are busy generating data only with probability . Suppose that the 1 Mbps link is prop trans t=0 t= trans prop trans t=dtrans prop trans to trans s=2.5⋅108 L=120 bits R=56 kbps. prop trans p=0.1 replaced by a 1 Gbps link. a. What is N, the maximum number of users that can be supported simultaneously under circuit switching?

Answer 1

hello your question is not properly structured below is the complete question

. Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1 Mbps link. Users are generating data at a rate of 100 kbps when busy, but are busy generating data only with probability . Suppose that the 1 Mbps link is replaced by a 1 Gbps link. a. What is N, the maximum number of users that can be supported simultaneously under circuit switching?

answer : N = 1000 users

Step-by-step explanation:

The maximum number of users (n) that can be supported simultaneously under circuit switching

N = Total transmission / rate of data generation by users

Total transmission = 1 Gbps = 1 * 10^9 bps

rate of data generation by user = 100 kbps = 10 * 10^4 bps

hence the maximum number of users that can be supported simultaneously

= ( (1* 10^9) / (10 * 10^4) )

= 10000 users