Answer:
Δp = -2 p₀
Step-by-step explanation:
The momentum is defined by
p = m v
In this case we write the initial and final momentum, we take as positive the direction towards the wall.
p₀ = m v
p_f = m (-v)
the negative sign is because the car is bouncing off the wall
the change of the moment is
Δp = p_f - p₀
Δp = - m v - m v
Δp = -2 mv
Δp = -2 p₀
we see that the change of moment is twice the moment, in the attachment we can see the vectors of these changes and the sign indicates the direction of the change at the moment