Question

Fill in the blanks so that the standard and factored forms match

-x^4-5x^3+__ x^2 +10x=(x+__)(2x-x^3)

Answer 1

-x^4-5x^3+2x²+ 10x = (x+5)(2x-x³)

Step by Step explanation

Naming the coefficient of x² as "a" and the independent temine of the first parenthesis as "b", we got:

-x^4-5x^3+ ax^2 +10x=(x+b)(2x-x^3)

- x⁴-5x^3+ ax^2 +10x = 2x²- x⁴+2bx-bx³

-5x^3+ ax^2 +10x = -bx³+2x²+2bx

( Matching the exponents)

For x: 2b= 10; b=10/2.

b=5

For x²: a=2

For x³: -b=-5

b=5