Question

Given the points R(6, -2) and T(-9, -7), find the coordinates of point S on line segment RT such that the ratio of RS to ST is 3:2. Your answer will be an ordered pair.

Answer 1

The coordinates of the point are (-3,-5)

Explanation:

Here, we want to find the coordinates of the point that divides the segment in the ratio 3:2

We shall use the internal division formula;

(x,y) = (mx2 + nx1)/(m + n) , (my2 + ny1)/(m+ n)

Where in this case;

(x1,y1) = (6,-2)

(x2,y2) = (-9,-7)

(m, n) = 3,2

Substituting these values;

(x,y) = (3(-9) + 2(6))/(3+2) , (3(-7) + 2(-2))/(3+2)

(x,y) = (-27 + 12)/5 , (-21 -4)/5

(x ,y) = (-15/5, -25/5)

(x , y) = (-3,-5)