Question

A 0.50 kg lead ball at 45 c is dropped into a calorimeter with water at 20 the final temperature of the ball-water system is 25c, what is the mass of the water? consider specific heat capacity of led = 128 / k * g degrees * c and specific heat capacity of water=4186 //kg^ c

Answer 1

.0612 kg

Step-by-step explanation:

I think your spec heat for lead should be 128 j /kg-K

Final lead temp is the same as the water 25 C Note that 1 K = 1 C degree

so lead goes from 45 to 25 C (or difference of 20 K)

Heat given up by the lead =

.5 kg * (20 K) * 128 j/ kg -C = 1 280 j

this heat is GAINED by the water going from 20 to 25 C

x kg * (5 C ) (4186 j/kg-C ) = 1 280 j

x = .0612 kg