Question

2t + -8 = 4 solve for t

Answer 1

`t=6`

Explanation:

`2t+\left(-8\right)=4`

`\longmapsto2t-8=4`

Add 8 to both sides:

`\longmapsto2t-8+8=4+8`

`\longmapsto2t=12`

Divide both sides by 2:

`\longmapsto(2t)/(2)=(12)/(2)`

`\longmapsto t=6`

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Answer 2

t=6

Explanation:

2t+-8=4

First let's get rid of -8 to have only our coefficient on one side. To do this we must add positive 8 on both sides. By adding -8 and positive 8 it cancels out leaving you with:

2t=12

Then you divide 2 from both sides to isolate the variable and you get:

t=6