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M(-3,2) is the midpoint of AP. If A has coordinates (-1,5), what are the
coordinates of P?

1 Answer

3 votes

Answer:

P(-5, -1)

Explanation:

If M is midpoint of AP then:


x_P-x_M=x_M-x_A\qquad\quad\ \wedge\qquad y_P-y_M=y_M-y_A\\\\x_P-(-3)=-3-(-1)\qquad\wedge\qquad y_P-2=2-5\\\\x_P+3=-3+1\qquad\quad\ \wedge\qquad\quad y_P-2=-3\\\\x_P=-3+1-3\qquad\quad\ \wedge\qquad\quad y_P=-3+2\\\\x_P=-5\qquad\qquad\ \wedge\qquad\qquad y_P=-1

User Amruth Lakkavaram
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