Question

4. Find three consecutive integers such that twice

the sum of the first and third is 24 more than the
second.

Answer 1

7, 8, 9

Explanation:

x, x+1, x+2

2(x+x+2) = x+1 + 24

4x + 4 = x + 25

4x -x = -4 + 25

3x = 21

/3 /3

x = 7

7, 8, 9

Answer 2

Sure, let's solve this step by step.

Step 1: Define the integers.
Let's denote the three consecutive integers as x, x+1, and x+2.

Step 2: Translate the problem into an equation.
The problem states that twice the sum of the first (x) and third (x+2) integers is 24 more than the second integer (x+1). This can be written as:
2 * (x + (x + 2)) = (x + 1) + 24

Step 3: Simplify the equation.
We can simplify this into: 4x + 4 = x + 25. Consequently, by deducting x and 4 from both sides of the equation, we get:
3x = 21

Step 4: Solve for x.
Dividing both sides by 3, we find that x is equal to 7.

Step 5: Identify the three integers.
Therefore, the three consecutive integers are 7, 8, and 9.

I hope this helps! Let me know if you have any questions.