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Solve for the inverse of: f(x)=1/8(x+1)^3

Solve for the inverse of: f(x)=1/8(x+1)^3-example-1

1 Answer

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Answer:
y=(8x)^{(1)/(3)} -1 or
y=\sqrt[3]{8x} -1

Explanation:

To find the inverse, you switch y with x and x with y. Then, you solve for y.


y=(1)/(8) (x+1)^3 [switch y with x and x with y]


x=(1)/(8) (y+1)^3 [multiply both sides by 8]


8x=(y+1)^3 [cube both sides]


\sqrt[3]{8x} =y+1 [subtract both sides by 1]


y=\sqrt[3]{8x} -1 or
y=(8x)^{(1)/(3)} -1

User Igal K
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