Question

An egg is dropped from a treehouse and takes 1.5 seconds to reach the ground. We can ignore air resistante What is the egg's displacement?

Answer 1

d = -11.025 m

Step-by-step explanation:

Given that,

An egg is dropped from a treehouse and takes 1.5 seconds to reach the ground. We need to find the egg's displacement. It can be calculated using second equation of motion as follows :

`s=ut+(1)/(2)at^2`

u is initial speed, the initial speed of egg is 0 as it was at rest initially.

a = -g (as the stone is coming downward direction)

t is time.

si is egg's displacement

`s=0-(1)/(2)gt^2\\\\s=(1)/(2)* 9.8* 1.5^2\\\\d=-11.025`

-ve sign shows the displacement of the egg in opposite direction of its motion and its magnitude is 11.025 meters.