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Gold has a specific heat of 129 J/kg K. How much heat would be given off when 50 kg of gold cools from 323 kg to 293 kg?
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Gold has a specific heat of 129 J/kg K. How much heat would be given off when 50 kg of gold cools from 323 kg to 293 kg?

User Saurabh
by
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1 Answer

4 votes

Answer:

Step-by-step explanation:

Q=m*c*ΔT

m=50 kG

C=129 j.kg^-1.k^-1

ΔT=323-293=30

now

Q=50*129*30=193500

User Robert Wysocki
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