Question

What is the slope of a line that contains the pair of points (6,-3) and (-5,-4)

Answer 1

Slope (m) =ΔY/ΔX=1/11= 0.090909090909091

θ =

arctan( ΔY ) + 180°ΔX=185.19442890773°

ΔX = -5 – 6 = -11

ΔY = -4 – -3 = -1

Distance (d) = √ΔX2 + ΔY2 = √122 = 11.045361017187

Equation of the line:

y = 0.090909090909091x – 3.5454545454545

or

y = 1x11– 39/11

When x=0, y = -3.5454545454545

When y=0, x = 39

Explanation: