Question

Dust falls on a certain metropolitan area at a rate of 67 mg·m−2·day−1. Major metallic elements in the dust include Al, Mg, Cu, Zn, Mn, and Pb. Mn accumulates at a rate of 0.06 mg·m−2·day−1. How many metric tons (1 metric ton = 1000 kg) of Mn fall on the 556 square kilometers of this metropolitan area in 5.0 years?

Answer 1

60.9 metric tons of Mn are accumulated

Step-by-step explanation:

The Mn accumulates at a rate of 0.06 mgm⁻²day⁻¹.

After 5.0years (5years * 365 = 1825days) will be accumulate:

0.06 mgm⁻²day⁻¹ * 1825 days =

109.5mgm⁻²

Now, 556km² are:

556 km² * ((1000m)² / 1km) = 5.56x10⁸ m²

In 5.56x10⁸ m² you will accumulate:

5.56x10⁸ m² * 109.5mgm⁻² = 6.09x10¹⁰mg are accumulated.

In kg:

6.09x10¹⁰mg * (1kg / 1x10⁶mg) = 6.09x10⁴kg.

In metric tons:

6.09x10⁴kg * (1 metric ton / 1000kg) =

60.9 metric tons of Mn are accumulated