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An object accelerates from rest to a velocity of 22 m/s over 35 m what was it’s acceleration
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An object accelerates from rest to a velocity of 22 m/s over 35 m what was it’s acceleration

User Orchid
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1 Answer

1 vote

Answer:

6.91 m/s/s

Step-by-step explanation:

First Solve for t (displacement)

t=2s/(v+u) 2x35m= 70m/22 m/s= 3.18 seconds

a=acceleration

v= final velocity

u= initial velocity

s= displacement

t= time

Then acceleration: a=v−u/t

a= 22m/s-0m/s = 22m/s divide by 3.18s = 6.918m/s/s

Use on-line calculator at calculatorsoup.com uniformly accelerated motion

User Arnyeinstein
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