Complete Question
A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes. What equation can you use to find the distance of the flowerbed from the hive?
Answer:
The equation is
![960 = (Z)/(9)+ (Z)/(6) + 780](https://img.qammunity.org/2021/formulas/mathematics/high-school/63tpyi3cxvrhxec0jzs5lo7svndhk2lw79.png)
Explanation:
From the question we are told that
The velocity of the bee is
The duration on the flowerbed is
![t = 13 \ minutes = 780 \ s](https://img.qammunity.org/2021/formulas/mathematics/high-school/1lmajzbd14m1vv4b50khjstdjlhtzvc6mm.png)
The velocity back to his hive is
![u = 6ft / s](https://img.qammunity.org/2021/formulas/mathematics/high-school/hcv5z8ow3ty4t6vups2dex7swb279zbb8r.png)
The total time away from it hive is
![t_t = 16 \ minutes = 960 \ s](https://img.qammunity.org/2021/formulas/mathematics/high-school/xvd85nx3vlb5abtxdk613r4ukgmn8p5qsa.png)
Now let assume the distance of the flower bed from the hive is Z
Generally the time taken for the bee to travel to the flower bed from its hive is
![t_1 = (Z)/(9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d6melmpc49ohf12wxut2t5uhtwzylsghyk.png)
The time taken for the bee to fly back to his hive is
![t_2 = (Z)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/jm7iux8pky4ukmsn2o66errdc2wjciuxck.png)
Generally the total time the bee spent outside of his house is mathematically represented as
![t_t = t_1 + t_2 + t](https://img.qammunity.org/2021/formulas/mathematics/high-school/5agb248lfdt4liklllm0o3h6gpbehgm8l3.png)
=>
![960 = (Z)/(9)+ (Z)/(6) + 780](https://img.qammunity.org/2021/formulas/mathematics/high-school/63tpyi3cxvrhxec0jzs5lo7svndhk2lw79.png)