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Your samples contained both Al and F, although the composition was not specified in this lab. Suppose you were given a second sample that contained the same amount of Al, but twice the amount of F. What changes would be observed in the data obtained in channel A, and how would this affect your calculated value for ti/2 of 2F?

A. There would be no observable changes in the data.
B. The intensity of 20F signal would be higher, and the lifetime would be twice as long.
C. The intensity of 20F signal would be higher, but the lifetime would be unchanged
D. The intensity of 28Al signal would be higher.

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Answer:

C. The intensity of 20F signal would be higher, but the lifetime would be unchanged

Step-by-step explanation:

The half live value is constant, life term of an exponentially decaying quantity, and it a property of the exponential decay equation. Half life does not decay on the initial concentration. Hence, there won't be any change in observation.

C. The intensity of 20F signal would be higher, but the lifetime would be unchanged

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