Answer:
a. Acceleration of the car is 2.62 m/s²
b. Time it takes the car to travel the length of the ramp is 9.16 secs
c. Distance traveled by the traffic is 210.7 m
Step-by-step explanation:
(a) To calculate the acceleration of the car,
From the question,
The car starts from rest, that is
The initial velocity, u = 0 m/s
Final velocity, v = 24.0 m/s
Distance covered by the car = 110 m
acceleration, a = ??
From one of the equations of kinematics for linear motion,
v² = u² +2as
Where v is the final velocity
u is the initial velocity
a is the acceleration
and s is the distance
Hence,
24.0² = 0² + 2(a)(110)
576 = 0 + 220a
576 = 220a
a = 576/220
a = 2.62 m/s²
This is the acceleration of the car
(b) For the time it takes the car to travel the length of the ramp
From
v = u + at
where t is the time
Then,
24.0 = 0 +2.62(t)
2.62t = 24.0
∴ t = 24.0/2.62
t = 9.16 secs
This is the time it takes the car to travel the length of the ramp
(c) For the distance the traffic travel while the car is moving the length of the ramp,
Velocity of the traffic = 23.0 m/s
Time spent by the traffic while the car is moving the length of the ramp = Time spent by the car while moving the length of the ramp
That is,
Time spent by the traffic while the car is moving the length of the ramp = 9.16 secs
From,
Velocity = DIstance / Time
Distance = Velocity × Time
Disatnce = 23.0 × 9.16
Distance = 210.68 m
Distance ≅ 210.7 m
This is the distance traveled by the traffic