Question

A geochemist in the field takes a 13.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 16.° C, and caps the sample carefully. Back in the lab, the geochemist filters the sample and then evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 0.143 g

Required:
Using only the information above, can you calculate the solubility of X in water at 15°C ? If you said yes, calculate it.

Answer 1

The answer is YES

The value is
`S = 110 \ g/L`

Step-by-step explanation:

From the question we are told that

The volume of the sample taken is v = 13.0 mL

The temperature is
`T = 16^oC`

The mass of the sample is
`m = 0.143 g`

Generally the solubility of the substance X is mathematically represented as

`S = (m)/(V)`

=>
`S =  (0.143  )/(13.0)`

=>
`S = 0.011 \  g/mL`

=>
`S = 110 \  g/L`