Question

Find the distance between A(–3, 5) and B(4, 2), to the nearest hundredth.

Answer 1

`d=7.62`

Explanation:

Start with the distance formula:

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Identify your values.

`x_1=-3\\x_2=4\\y_1=5\\y_2=2`

Substitute.

`d=√((4-(-3)^2+(2-5)^2)`

The
`-3` becomes positive as it's being multiplied by a negative.

`d=√((4+3)^2+(2-5)^2)`

Solve what is in parentheses.

`d=√((7)^2+(-3)^2)`

Square what is in parentheses.

`d=√(49+9)`

Add.

`d=√(58)`

Find the square root (I usually do four digits after the decimal).

`d=7.6157`

Round to the nearest hundredth.

`d=7.62`