Final answer:
The scalar components of the fly's displacement are -3.0 m in the x-direction, 3.0 m in the y-direction, and -2.0 m in the z-direction. The vector component form of the displacement is Δr = (-3.0ı, 3.0ı, -2.0ı) m, and its magnitude is approximately 4.69 m.
Step-by-step explanation:
The student asked for the scalar components of the fly's displacement vector and its magnitude when its position changes within a Cartesian coordinate system.
To calculate the scalar components of the displacement, we subtract the initial position coordinates from the final position coordinates:
Δx = xf - xo = 1.0 m - 4.0 m = -3.0 m
Δy = yf - yo = 4.5 m - 1.5 m = 3.0 m
Δz = zf - zo = 0.5 m - 2.5 m = -2.0 m
Therefore, the displacement vector in vector component form is Δr = (-3.0ı, 3.0ı, -2.0ı) m.
To find the magnitude of the displacement vector, we use the Pythagorean theorem:
| Δr | = √((-3.0 m)2 + (3.0 m)2 + (-2.0 m)2) = √(9 + 9 + 4) m = √22 m ≈ 4.69 m