Question

Please help me, I need an answer as soon as possible.

Answer 1

`\huge\boxed{\sf x = \pm √(7) }`

Explanation:

Given function:

`f(x)=x^2-7`

We can also write it as:

`y =x^2-7`

x-intercept is the point where y = 0

Put y = 0 in the above equation

`0=x^2-7\\\\Add \ 7 \ to \ both\ sides\\\\7 = x^2\\\\Take \ sqrt \ on \ both \ sides\\\\\pm √(7) =x\\\\x = \pm √(7) \\\\\rule[225]{225}{2}`