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The volume of pyramid A is the volume of pyramid B. If the height of pyramid B increases to twice that of pyramid A, the new volume of pyramid B is the volume of pyramid A.

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Given :

Two pyramid with same volume .

To Find :

If the height of pyramid B increases to twice that of pyramid A, the new volume of pyramid B .

Solution :


V_a=V_b

Volume of pyramid is given by :


V=\frac{\text{Area of base}* height}{3}\\\\V=(Ah)/(3)

Now , h'=3h


V'_b=(Ah')/(3)\\\\V'_b=3(Ah)/(3)\\\\V'_b=3V_a

Therefore , new volume of pyramid B is 3 times the value of pyramid A .

Hence , this is the required solution .

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