Question

If 30.2 g of CaO is added to 34.5 g of HCl and 6.35 g of water is formed, what

is the percent yield?​

Answer 1

Balanced chemical reaction is :

`CaO+2HCl--> CaCl_2+H_2O`

Also 30.2 g of CaO is added to 34.5 g of HCl and 6.35 g of water is formed.

Now , percentage yield is given by :

`\% \ Yield = (Actual\ Yield)/(Theoretical\ Yield )* 100\%`

Moles of CaO ,
`n_1=(30.2)/(56)=0.54\ moles`

Moles of HCl ,
`n_2=(34.5)/(36.5)=0.95\ moles`

Now , 2 moles of HCl react with 1 mole of
`H_2O` .

So , moles of
`H_2O` :

`n=(0.95)/(2)\\\\n=0.475\ moles`

Mass of water produced :

`m = 0.475 * 18\ g\\\\m=8.55\ g`

But in practical 6.53 g of water is produced .

So ,

`\% \ Yield = (6.35)/(8.55 )* 100\%\\\\\% \ Yield =74.27\%`

Therefore, percent yield is 74.27 %.

Hence, this is the required solution.