Answer:
The optimal solution is 3 standard telephones and 10 deluxe telephones for a maximum profit of $1,470.
Step-by-step explanation:
we have to maximize profit following the equation 90s + 120d
the constraints are:
30s + 35d ≤ 450
10s + 15d ≤ 180
d ≥ 6
s ≥ 0
using solver, the optimal solution is 3 standard telephones and 10 deluxe telephones for a maximum profit of $1,470.
we can check our solution:
(90 x 3) + (120 x 10) = 1,470
(30 x 3) + (35 x 10) = 440 ≤ 450
(10 x 3) + (15 x 10) = 180 ≤ 180
10 ≥ 6
3 ≥ 0