Question

PLEASE HELP ME WITH THIS

Answer 1

C.

Explanation:

So we have the equation:

`y=√(x-3)`

This is a square root equation.

For square root equations, the radicand(s) must be positive.

Therefore, to find the domain, set the radicand to be greater than or equal to 0:

`x-3\geq 0`

Solve for x. Add 3 to both sides:

`x\geq 3`

Therefore, our domain must be greater than or equal to 3.

In set notation, this is:

`\{x:x\geq 3\}`

Therefore, our answer is C.

Answer 2

All we need to do is solve for the 0 of the function.

Solution:

0 = √x-3

0^2 = x - 3

0 = x - 3

3 = x

The domain is greater than or equal to 3 and this can be written as x ≥ 3 or in other words, Option 3.

Best of Luck!