Question

How many grams of calcium oxide will be produced in a closed vessel containing 20.0 kg of calcium and 20.0 kg of oxygen gas if the reaction goes to completion? (atomic mass of calcium = 40.1 amu)

Answer 1

Step-by-step explanation:

The mass of Calcium oxide that will be produced in a closed vessel is 27984.1311 g. The Number of moles is defined as given mass over molar mass.

Calculation of Number of moles:

Number of moles = Given mass / Molar mass

For Calcium :-

Mass of calcium = 20.0 kg = 20000 g ( 1 kg = 1000 g )

Molar mass of calcium = 40.078 g/mol

Thus,

Number of moles = 20000 g / 40.078 g/mol

Number of moles = 499.02 moles

For oxygen gas :-

Mass of oxygen gas = 20.0 kg = 20000 g ( 1 kg = 1000 g )

Molar mass of oxygen gas = 31.999 g/mol

Thus,

Number of moles = 20000 g / 31.999

Number of moles = 625.19 moles

According to the given reaction:

2 moles of calcium reacts with 1 mole of oxygen gas

Also,

1 mole of calcium reacts with 1/2 mole of oxygen gas

So,

499.0269 mole of calcium react with mole of oxygen gas

Moles of oxygen gas = 249.5135 moles

Available moles of oxygen gas = 625.0195 moles

Limiting reagent is the one which is present in small amounts. Thus, calcium is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

2 moles of calcium produces 2 moles of calcium oxide

So,

1 mole of calcium produces 1 mole of calcium oxide

Also,

499.0269 moles of calcium produces 499.0269 moles of calcium oxide

Moles of calcium oxide = 499.0269 moles

Molar mass of calcium oxide = 56.0774 g/mol

Mass of calcium oxide = Moles × Molar mass = 499.0269 * 56.0774 g = 27984.1311 g

27984.1311 g of calcium oxide will be produced.