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What positive value of x that makes the equation true: x^3 =125^-1

User Gogi
by
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1 Answer

5 votes

Answer:

x = 1/5

Explanation:

Take the cube root:


x^3=125^(-1)\\\\x=\left((1)/(125)\right)^{(1)/(3)}=\frac{1}{\sqrt[3]{125}}\\\\\boxed{x=(1)/(5)}

User TheTXI
by
6.4k points