Question

Seven times the smaller

of two consectative even

integers

is the same as

-300 minus 4 times the

largor integer. Find the integers

Answer 1

Given:

Seven times the smaller of two consecutive even integers is the same as -300 minus 4 times the larger integer.

To find:

The integers .

Solution:

Let the smaller even integer be x.

So, larger even integer is x+2 because they are consecutive even integers.

Seven times the smaller integer = 7x

-300 minus 4 times the larger integer = -300-4(x+2)

Now,

`7x=-300-4(x+2)`

`7x=-300-4x-8`

`7x+4x=-308`

`11x=-308`

Divide both sides by 11.

`x=(-308)/(11)`

`x=-28`

So, the smaller even integer is -28.

`x+2=-28+2=-26`

So, the larger even integer is -26.