Question

A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound of the ball hitting the pins 2.79 s after the ball is released from his hands.

Answer 1

Let , speed of bowling ball is v .

Time taken by ball to hit the pins ,
`t=(16.5)/(v)` .

Speed of sound , u = 343 m/s .

Time taken by sound to reach ear ,
`T=(16.5)/(343)=0.048\ s` .

Now ,

Time taken by sound to hear after release :

`2.79=(16.5)/(V)+0.048\\\\2.79-0.048=(16.5)/(V)\\\\2.742=(16.5)/(V)\\\\V=(16.5)/(2.742)\\\\V=6.02\ m/s`

Hence , this is the required solution .