Question

Suppose​ s(t) is the position of an object moving along a line at time t0. What is the average velocity between the times ta and t​b?

Answer 1

`V = (s(t_b) - s(t_a))/(t_b -t_a)`

Step-by-step explanation:

Given;

position of the object as s(t)

The average velocity is given by;

`V = (s(t_b) - s(t_a))/(t_b -t_a)`

where;

s(tb) is the object's final position at time tb

s(ta) is the initial position of the object at time ta

tb is the final time of the object's displacement

ta is the initial time of the object's displacement