Question

An object is launched horizontally at a velocity of 19 m/s from the top of a building. It falls vertically a distance of 24m before it reaches the ground. How long does this projectile travel before reaching the ground?

Answer 1

2.2 s

Step-by-step explanation:

His vertical initial velocity u =0

vertical displacement h = 24 m .

vertical acceleration g = 9.8 m /s²

h = ut + 1/2 gt²

24 = 1/2 x 9.8 x t²

t = 2.2 s .

Time of fall = 2.2 s