Question

30. When asked his age, the algebra teacher said, "If you

square my age, then subtract 23 times my age, the
result is 50. How old is be?
F. 23
G. 25
H. 27
J. 46
K. 50

Answer 1

25 years old

Explanation:

Let the teacher's age be a.

Then:

a^2 - 23a = 50

In standard form, this quadratic is

x^2 - 23a - 50 = 0

Factoring this, we get (x - 25)(x + 2) = 0

So a is either 25 or a is -2. Only a = 25 is relevant here.

The teacher is 25 years old (Answer G)