Answer:
1. 158 unit^2
2. 225 cm^2
3. 303 unit^2
Explanation:
The first thing you should do is separate the figures by imaginary lines to form 2 or more rectangles (done in attachment).
1. You can see that the lowest line is 20 which is shared by both the rectangle A and B. The length of the smaller rectangle is 6 meaning that the length of rectangle A is 20-6=14
Now we need the breadth as the area is equal to l×b
To calculate the total area of the figure we have to add the areas of all rectangles. We have all the necessary details for the area of rectangle A so
A= 10×14= 140 unit^2
Now as cited earlier, we need all rectangle areas to find the Area of the figure. You can see that 10 is the breadth shared by both rectangles but 7 is only shared by bigger rectangles.
The breadth of smaller (rectangle B) is = 10-7=3
We have the length of rectangle b and breadth of rectangle b so:
A= 6×3=18 unit^2
Area of total figure=140+18= 158 unit^2
2. Find the length and breadth of both rectangles as I explained earlier.
We have all the details for triangle C so A= 18×7= 126 cm^2
16 m is shared by C and D and 7 is shared by only D so the share of the length of C= 16-7= 9cm
A= 9×11= 99 cm^2
T.A= 126+99=225 cm^2
3. 19 is shared by E and F and 9 is only shared by F so to find the breadth of E we can 19-9= 10 cm
We have all the details so A of E=10×15=150 unit^2
A of F= 9×17= 153 unit^2
T.A= 150+153= 303 unit^2