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John had a bag of marbles as shown below.

What is the probability that John selects a green marble, replaces it, and then selects a
green marble?
3 green marbles
4 blue marbles
2 red marbles
1 yellow marble

A.9/100
B.1/ 10
C.1/15
D.1/50

1 Answer

8 votes

Answer:


\sf A) \quad (9)/(100)

Explanation:

Given:

  • 3 green marbles
  • 4 blue marbles
  • 2 red marbles
  • 1 yellow marble

Total number of marbles = 3 + 4 + 2 + 1 = 10


\sf Probability\:of\:an\:event\:occurring = (Number\:of\:ways\:it\:can\:occur)/(Total\:number\:of\:possible\:outcomes)

Probability of selecting a green marble on first pick:


\implies \sf P(green\:marble)=(3)/(10)

Probability of selecting a green marble on second pick:


\implies \sf P(green\:marble)=(3)/(10)

(as the 1st pick was replaced)

Therefore,


\implies \textsf{P(green marble) and P(green marble)} \sf =(3)/(10) * (3)/(10)=(9)/(100)

User Frnhr
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