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The midpoint of AB is M (6,1). If the coordinates of A are (4, 8), what are the coordinates of B?

User Dynom
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1 Answer

5 votes

Answer:


B = (8,-6)

Explanation:

Given


A = (4,8)


M = (6,1) -- Midpoint

Required

Find B

This question will be solved using midpoint formula;


M(x,y) = ((x_1 + x_2)/(2),(y_1 + y_2)/(2))

Where


A(x_1,y_1) = (4,8)


M(x,y) = (6,1)

Substitute these values in the midpoint formula;


(6,1) = ((4 + x_2)/(2),(8+y_2)/(2))

By comparison; we have:


(4 + x_2)/(2) = 6 -- (1)


(8 + y_2)/(2) = 1 -- (2)

Solving (1)


(4 + x_2)/(2) = 6

Multiply both sides by 2


4 + x_2 = 12

Subtract 4 from both sides


x_2 = 8

Solving (2)


(8 + y_2)/(2) = 1

Multiply both sides by 2


8 + y_2 = 2

Subtract 8 from both sides


y_2 = -6

Hence:


B = (8,-6)

User Giancarlo Ventura
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