Question

Find the midpoint of the segment whose endpoints are (8,6) and (-2,-8).

(3,-1)
(5,7)
(7,-5)
(4,-1)

Geometry

Answer 1

`\huge{ \fbox{ \sf{ \: ( \: 3 \: ,  \: - 1 \: )}}}`

Explanation:

`\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}`

`\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and \: B(-2,-8) \: be \: (x2 \:, y2)}}`

`\underline{ \sf{Finding \: the \: midpoint}}`

`\boxed{ \rm{Midpoint \: = \: ( (x1 + x2)/(2) \: ,  \: (y1 + y2)/(2) )}}`

`\mapsto{ \sf{Midpoint = ( (8 + ( - 2))/(2) \: ,  \: (6 + ( - 8))/(2) )}}`

`\mapsto { \sf{Midpoint = ( (8 - 2)/(2) \: ,  \: (6 - 8)/(2) }})`

`\mapsto{ \sf{Midpoint = ( (6)/(2) \: ,  \: ( - 2)/(2)) }}`

`\mapsto{ \sf{Midpoint = (3 \: \: ,  - 1)}}`

Hope I helped!

Best wishes!! :D

~
`\sf{TheAnimeGirl}`