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2 votes
1 less than the square of a number.
Don’t know the answer

1 Answer

4 votes

Answer:


x<-1\quad \mathrm{or}\quad \:x>1

Explanation:

Let the unknown number be x


1 < x^(2) \\\\Switch\:sides\\\\x^2>1\\\\\mathrm{For\:}u^n\:>\:a\mathrm{,\:if\:}n\:\mathrm{is\:even}\mathrm{\:then\:}u\:<\:-\sqrt[n]{a}\:or\:u\:>\:\sqrt[n]{a}\\\\x<-1\quad \mathrm{or}\quad \:x>1

User John Stritenberger
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