Answer:
0.16 cal/g°C
Step-by-step explanation:
The following data were obtained from the question:
Mass (M) = 15 g
Heat (Q) = 60 calories
Temperature change (ΔT) = 25 °C
Specific heat capacity (C) =..?
We, can obtain the specific heat capacity of the substance as shown below:
Q = MCΔT
60 = 15 × C × 25
60 = 15 × 25 × C
60 = 375 × C
Divide both side by 375
C = 60/375
C = 0.16 cal/g°C
Therefore, the specific heat capacity of the substance is 0.16 cal/g°C