Answer:
RbH(s)+ H2O(l) → RbOH + H2
Step-by-step explanation:
The reaction is;
RbH(s)+ H2O(l) → Product
From Ahmad's statement, we know that the product of he reaction is going to be an Hydroxide (-OH) and hydrogen gas (H2)
So we have;
RbH(s)+ H2O(l) → RbOH + H2