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If f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (fog)(x)?

1 Answer

4 votes

Answer:

(fog)(x) = f(g(x)) = 3(x^2 + 1 ) + 2

Explanation:

For this problem, you simply need to understand the notation (fog)(x) is equivalent to f ( g ( x ) ). This means you simply plug the function g(x) into each x within the function of f(x). Let's do this:

f(x) = 3x + 2

g(x) = x^2 + 1

f(g(x)) = 3(x^2 + 1 ) + 2

(fog)(x) = f(g(x))

Cheers.

User Bhelm
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