Question

What is the electric field produced by this charge at point P, which is on the x-axis, 9.83 mm from the origin

Answer 1

Given :

Distance of point P from the origin is , d = 9.83 mm .

To Find :

The electric field produced by this charge at point P , if charge is placed at origin .

Solution :

Let , charge on origin is q .

Electric field at point P is given by :

`E=(kq)/(r^2)` ..... ( 1 )

Here , k is constant ,
`k=9* 10^(9)\ N \ m^2/C^2` .

Putting value of k and r in above equation , we get :

`E=(q* 9* 10^9)/((9.83* 10^(-3))^2)\ N/C\\\\E=(9.31* 10^(13))q\ N/C`

Hence , this is the required solution .