Question

What is the value of this expression if h=8 ,j= -1 , and k= -12? j³k/h0

Answer 1

`(j^3k)/(h^0) = 12`

Explanation:

Given

`h=8`

`j= -1`

`k= -12`

Required

Determine
`(j^3k)/(h^0)`

To do this, we simply substitute the values of h,j and k in the given expression

`= ((-1)^3 * (-12))/(8^0)`

Solve the denominator

`= ((-1)^3 * (-12))/(1)`

Evaluate all exponents

`= (-1 * (-12))/(1)`

Open Bracket

`= (-1 * -12)/(1)`

`= (12)/(1)`

`= 12`

Hence:

`(j^3k)/(h^0) = 12`