1 Answer

Life Of Madness · Answer 1 · 2021-11-18T20:11:27+0000

Answer:

The muon lepton number in Left Hand Side of reaction is
$L_(\mu ) = 1$ that is for
$\mu^(-)$

The muon lepton number in Right Hand Side of reaction is
$L_{v_(\mu)} = 1$ that is for
$v_(\mu)$

Step-by-step explanation:

From the question we are told that

The reaction is
$\mu^(-) \to e^(-) + v_e + v_(\mu)$

Now the looking at the equation,

The muon lepton number in Left Hand Side of reaction is
$L_(\mu ) =  1$ that is for
$\mu^(-)$

The muon lepton number in Right Hand Side of reaction is
$L_{v_(\mu)} =  1$ that is for
$v_(\mu)$

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