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The hydrogen molecule will start to vibrate at temperatures above roughly 1000 K. At this high temperature, what is the ratio of the internal energy of hydrogen gas to the internal energy of helium gas, assuming that the number of molecules in each gas is the same. Write your answer as a number in normal form, as described in the instructions.

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Answer:

Step-by-step explanation:

At the temperature of 1000K , hydrogen will have following degree of freedom

translational = 3

rotational = 2

vibrational = 1

Total = 6

Internal energy = 6N x 1 /2 k T where N is no of molecules

E₁ = 3 N kT

At the temperature of 1000K , helium will have following degree of freedom

translational = 3

rotational = 0

vibrational = 0

Total = 3

Internal energy = 3N x 1 /2 k T where N is no of molecules

E₂ = 3 / 2 N kT

Ratio = E₁ / E₂

= 2

User Martin Calvert
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